given that sin A =a/b find tan A
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sin A =a/b
opposite=a
hypotenuse =b
adjacent= b^2-a^2 by pythagoras theorem
tan A=a /b^2-a^2
opposite=a
hypotenuse =b
adjacent= b^2-a^2 by pythagoras theorem
tan A=a /b^2-a^2
Anonymous:
Right
Answered by
1
sinA=a/b,
tanA=a/✓(b^2-a^2)
tanA=a/✓(b^2-a^2)
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