given that sin A =a/b , then cosA
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Given
Sin A= a/b
We know that
Sin^2 A+ Cos^2 A= 1
Therefore Cos^2 A = 1- Sin^2 A
Cos A= √1-Sin^2 A
We Know Sin A = a/b
On squaring Both sides
We get Sin^2 A= a^2/b^2
On substituting the above value,we get
Cos A= √ 1-a^2/b^2
Cos A= √b^2-a^2 / √b^2
Therefore, Cos A= /b^2 - a^2 / b
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