Question

Given that sin(A-B)=sinA.cosB-cosA.sinB. Find the value of sin 15° in two ways 1) Taking A=60° and B=45° and 2) Taking A=45° and B=30°​

Answer 1

Step-by-step explanation:

1) sin(A-B)=sinAcosB-sinBcosA

sin(60-45) = sin60*cos45-sin45*cos60

√3/2*1/√2-(1/√2*√/2)

√3-1/2√2

2)sin45*cos30-sin30*cos45

= 1/√2*√3/2-(1/2*1/√2)

√3-1/2√2

hope it helps