Question

Given that sinƟ=a/b ,then tanƟ is equal to​

Answer 1

Step-by-step explanation:

sin Θ = a/b

cosΘ = $\sqrt{1 -(a^2/b^2)}$ =

$\sqrt{(b^2-a^2)/b^2}\\= (\sqrt{b^2-a^2}/b )$

tanΘ = sinΘ/cosΘ = $(a/b) (b/\sqrt{b^2-a^2} = \frac{a}{\sqrt{b^2-a^2} }$