Given that sin ϴ = c/d, cos ϴ = a) d/c b) √ (d 2 – c 2 )/d c) d/√ (d 2 – c 2 ) d) c/√ (d
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Answer:
a) d/c fdhstsriaydyyatsucohphirryjhgeeyuibbdswyoibvsukhsydudtwhtsgndykeocjrd
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Answer:
sin thetha=c/d
hypotenuse =d
perpendicular =c
base=(h^2-p^2)^1/2
base=(d^2-c^2)
cos theta=b/h
cos thethq=root(d^2-c^2)/d
Step-by-step explanation:
answer is b
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