Given that sin theta = a/b, find tan theta
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Step-by-step explanation:
Given,
Sin thetha = a/b
We know sin ø = opposite side/hypotenuse
So a = opposite side and b = hypotenuse
Tan ø = opposite side/adjacent side
Using pythagoras theorem ,
AB ^ 2 + BC ^2 = AC ^2
a^2 + BC^2 = b^2
BC^2 = b^2-a^2
BC = √b^2-a^2
Tan ø = a/√b^2-a^2
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