given that sin theta =a /b, then cos theta is equal to
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Answer:
we know that sin theta =perpendicular/hypotaneous.
So, here a is perpendicular and b is hypotaneous.
Now, we also know that (hypotaneous)^2=(base)^2 + (perpendicular)^2. Therefore from here we get base= √(hypotaneous)^2-(perpendicular)^2.
Now, cos theta = base/hypotaneous.
Therefore, cos theta = (√b^2 - a^2)/b
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