given that sin theta is 3/5 find cos theta and tan theta
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Answer:
Sinθ = 3/5
sin²θ = 9/25
1 - cos²θ = 9/25 { sin²θ + cos²θ = 1}
cos²θ = 1-(9/25)
cos²θ = 16/25
cosθ = 4/5
∴ tanθ = sinθ/cosθ = 3/4
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