Question

given that sin thetha = a/b then tan thetha​

Answer 1

ANSWER :-

a/√(a-b)

EXPLANATION -

Given , Sin theta = a/b

perpendicular/hypotenuse = a/b

let ,

perpendicular = ax

hypotenuse = bx

so ,

base = √(perpendicular ^2 - base^2)

= √(ax^2-bx^2)

= √(a-b) x

so tan theta = perpendicular/base

= ax/√(a-b)x

= a/√(a-b)