Question

given that sin thita = a/b , then tan thita =​

Answer 1

Answer:

Step-by-step explanation:

sin theeta = a/b

or height / hypotenuse = ax/bx

therefore base = $\sqrt{b^2 - a^2$ x

so tan theeta = height / base

i,e a/$\sqrt{b^2 - a^2$

hope it helps;)

Answer 2

Step-by-step explanation:

sin theeta = a/b

or height / hypotenuse = ax/bx

therefore base = \begin{gathered}\sqrt{b^2 - a^2\\\end{gathered} x

so tan theeta = height / base

i,e a/\begin{gathered}\sqrt{b^2 - a^2\\\end{gathered