Question

Given that sin Z =. a/b, then cos Z is equal to

b/a
b/√(b^2-a^2 )
√(b^2-a^2 )/b
a/√(b^2-a^2 )​

Answer 1

Answer:

Option C.

Sin Z = p/h = a / b

h² = p²+b²

b² = a²+ x ²

x= √ b²-a²

Cos Z = b/ h = √b²-a²/ b

Answer 2

Answer:

cos Z = √(b² - a²)/b

Step-by-step explanation:

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