Given that sina+2cosa=1then find the value of 2sina_cosa
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Given,
sinA + 2cosA = 1———(i)
or, sinA + 2cosA = sin²A + cos²A
or, sinA - sin²A = cos²A - 2cosA
or, sinA(1 - sinA) = cosA(cosA - 2)
or, sinA × 2cosA = cosA(cosA - 2) [From equation--(i)]
or, 2sinA = cosA - 2
or, 2sinA - cosA = -2
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