Question

given that sina =√3/2 and c0s β =0 then the value of the β-a is​

Answer 1

$\sin \: a = \frac{ \sqrt{3} }{2} \\ \implies a = 60° \\ \cos \beta = 0 \\ \implies \beta = 90° \\ \\ \beta - a \\ = 90° - 60° \\ = 30°$