Given that: SinA = a/b, then cosA = ? *
3 points
√(b² - a²)/a
a/b
b/a
√(b² - a²)/b
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Answer:
√ (b²-a²)/b
Step-by-step explanation:
sin²A= (a/b)²=a²/b²
sin²A + cos² A = 1
cos² A =1 - sin²A
= 1 - a²/b²
= b²-a²/b²
cosA = √ (b²-a²)/b ..... taking sq root
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