Question

Given that: SinA = a/b, then cosA = ?
(a) b/a
(b) a/b
(c) None​

Answer 1

Answer:

hey here is your answer

pls mark it as brainliest

Step-by-step explanation:

$so \: here \: SinA = a/b$

$also \: then \: using \: now \\ sin \: square \:A + cos \: square \: A = 1$

$ie \: cos \: square \: A = 1 - sin \: square \: A$

$= 1 - (a \div b) \: square \\ = 1 - a \: square \div b \: square$

$= b \: square - a \: square \div b \: square \\ so \: taking \: square \: roots \: on \: both \: sides \\ we \: get$

cos A=root of b square-a square÷b

hence option c ie none off these is correct answer