Question

Given that sinA = ab , then tanA = ​

Answer 1

sinA = A/B = P/H

P = A and H = B

By Pythagoras Theorem,

H^2 = B^2 + P^2

B^2 = H^2 - P^2

B^2 = b^2 - a^2

B = √b^2 - a^2

Therefore,

tan = P/ B = a / √b^2 - a^2

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