Given that tan theta=1/root 3
find : cosec square theta-sec square theta / cosec2 theta + sec square theta
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tan@=1/root3
here @=30'
....
(cosec^3@-sec^2@)/(cisec^2@+sec^2@)
{cosec^2(30')-sec^2(30')}/{cosec^2(30')+sec^2(30')}
{(2)^2-(2/root3)^2}/{(2)^2+(2/root3)^2}
{4-4/3}/{4+4/3}
8/16=1/2=.5
here @=30'
....
(cosec^3@-sec^2@)/(cisec^2@+sec^2@)
{cosec^2(30')-sec^2(30')}/{cosec^2(30')+sec^2(30')}
{(2)^2-(2/root3)^2}/{(2)^2+(2/root3)^2}
{4-4/3}/{4+4/3}
8/16=1/2=.5
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