Question

given that tan threta =1/root3, calculate all the t ratios​

Answer 1

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$tan \: \theta = \frac{p}{b} = \frac{1}{ \sqrt{3} }$

Iɴ ᴀ ᴛʀɪᴀɴɢʟᴇ ,

p = 1

b = √3

By using Pythagoras theorem :-

h² = b² + p²

h² = (√3)² + (1)²

h² = 3 + 1

h² = 4

h = √4

h = 2

$sin \: \theta \: = \frac{p}{h} = \frac{1}{2} \\ \\ cos \: \theta \: = \frac{b}{h} = \frac{ \sqrt{3} }{2} \\ \\ cot \: \theta = \frac{b}{p} = \sqrt{3} \\ \\ sec \: \theta = \frac{h}{b} = \frac{2}{ \sqrt{3} } \\ \\ cosec \: \theta = \frac{h}{p} = 2$

Answer 2

Question ⤵️

given that tan threta =1/root3, calculate all the t ratios

Answer ⤵️

Given:-

$\tan(theta) = \frac{1}{ \sqrt{3} }$

Solution:-

Attached in the given picture above.