Question

given that tanB=m/n find cos B​

Answer 1

Answer:

cosB=n/√m^2+n^2

Step-by-step explanation:

cosB=adjacent side /hypotenuse

so,cosB=n/√m^2+n^2

Answer 2

Answer:

Question:

• tanB=m/n find cos B

Solution:

From Question,

${ \sf{TanB = \frac{opposite}{adjacent} = \frac{m}{n} }}$

We know that,

• ${ \sf{CosB = \frac{adjacent}{hypotenuse} }}$

For Finding Hypotenuse We have to use Pythagorean theorm

• Hypotenuse² = opp² + Adj²

$: { \implies{ \sf{ {hyp}^{2} = {opp}^{2} + {adj}^{2} }}} \\ \\ : { \implies{ \sf{ {hyp}^{2} = {m}^{2} + {n}^{2} }}} \\ \\ : { \implies{ \sf \bold{ hyp = \sqrt{ {m}^{2} + {n}^{2} } }}}$

$\therefore{ \sf{CosB = \frac{ n}{ \sqrt{ {m}^{2} + {n}^{2} } } }}$