Math, asked by PratyushMallik19, 1 year ago

Given that tany=x2, what is the value of dydx?

Answers

Answered by sibiroopan
0

Diff of tanx is sec^2x.so,

sec^2x×dy/dx = 2. bcoz diff of x=1.

dy/dx=2/sec^2x

dy/dx=2cos^2x. bcoz 1/secx=cosx

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