Question

given that $a \: sinB + b \: sinB = c \:$ prove:--->

$= > ({a \: cosB - b \: sinB}) = \sqrt{ {a}^{2} + {b}^{2} - {c}^{2}.}$

​

Answer 1

❣Holla user.❣

Hope it helps u^_^

At last we are using the formulae of (a-b)^2=a^2+b^2-2ab

Hope u understand now

Answer 2

Question might be wrong.., Because when I substitute B=30 degrees, LHS does not equal to RHS...

Once check the question and ask it once again

Hope you find my advice helpful...