Question

Given that the 11 term of an arithmetic progression is 43 and that of the first term is 3 find the 4 term

Answer 1

Answer:

15

Step-by-step explanation:

$T_{11}$ = a + 10d

43 = 3 + 10d

40 = 10d

d = 4

$T_{4}$ = a + 3d

   = 3 + 3(4)

   = 3 + 12

   = 15