given that the abundance of isotopes fe 54,fe 55 and fe are 5%,90%,and 5% respectively. the average atomic mass of iron is.?
Answers
Answered by
1
Answer:
55.84
Explanation:
the formula to solve this particular question is
avg atomic mass=m1*p1+m2*p2+.........
Answered by
1
Answer:
Hello friends,
Just you have to multiply with masses * the abundance %
Explanation:
We know that fe 54 & fe 55 with 90% and 5%.
54*90/100+55*5/100
=48.6+2.75
=51.35%
Therefore the abundance %of fe 54 & fe 55 is 51.35%
Thank you...
anusharamesh:
thanks
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