Question

given that the abundances of istopes 54fe,56fe and 57fe are 5%,90%and 5% respectively the atomic mass of fe is:​

Answer 1

QUESTION => given that  abundances of istopes 54fe,56fe and 57fe are 5%,90%and 5% respectively the atomic mass of fe is:​

(A) 55.85 g/ mol

(B) 55.95 g/mol

(C) 55.75 g / mol

(D) 56.05 g / mol

ANSWER

☣. Given

☣ 54 fe , 56 fe , and 57 fe

Ai => atomic mass , Xi => mole fraction

Now coming Average atomic mass of fe

☣. Fe => ( 54 X 5 ) +( 56 X 90 ) + ( 57 X 5)

                ------------------------------------------------

                               100

By calculating we will get the answer as 55.95 //

☣. Option (B) 55.95 g/mol