Given that the atmospheric pressure is 10mH2O. What is the pressure exerted on the bottom of a 3m pool?
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Answer:
Let atmospheric pressure =P
o
=1.05×10
5
Pa
Pressure 10m below surface of lake,
P=P
o
+ρgh
=1.05×10
5
+1000×9.8×10
−1.99×10
5
Pa
=2 atm (ρ→ Density of water =1000 kg/m
3
, g=9.8m/s
2
h→ Depth=10m).
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