Question

given that the c. s. a of a right circular as 88cm² and its base diameter as 2cm , find the height of the cylinder​

Answer 1

Given :

• c. s. a of a right circular cylinder = 88cm²

• diameter of base = 2cm

To find :

• height of cylinder

Formula used :

• CSA of cylinder = 2πrh

• Radius ( r) = diameter / 2

Solution :

To find radius of base of cylinder use the given formula :-

⟹ Radius ( r) = diameter / 2

⟹ Radius ( r) = 2 / 2

⟹ Radius ( r) = 1 cm

Now we will find height :-

CSA of cylinder = 2πrh

where :-

• r = radius = 1 cm
• h = height
• π = 22/7

⟹ 88 = 2 × 22/7 × 1 × h

⟹ 88 = 44/7 × h

⟹ 88×7 = 44× h

⟹ (88×7) /44= h

⟹ 2×7= h

⟹ h= 2×7

⟹ h= 14 cm

Answer : 14 cm

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Verification of answer :

To verify your answer, put h = 14 , r = 1 , π = 22/7 in :- CSA of cylinder = 2πrh. If you get 88 cm² as CSA then your answer is right.

CSA of cylinder = 2πrh

CSA of cylinder = 2 × 22/7 × 1 × 14

CSA of cylinder = 2 × 22 × 1 × 2

CSA of cylinder = 88 cm²

hence verified

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Learn more :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

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