Given that the equation 12x^3-4x^2-5x+2 has two zeros equal, find all the zeros.
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2x3-4x2-5x+2=0. Two solutions were found : ... Equation at the end of step 2 : (((22•3x3) ... Thoughtfully split the expression at hand into groups, each group having two terms : Group 1: ... 3.3 Find roots (zeroes) of : F(x) = 12x3-4x2-5x+2 .... Since all these terms are equal to each other, it actually means : 2x-1 = 0. Add 1 to ...
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