Math, asked by nitinverma20, 1 year ago

Given that the equation ax^2+bx+c=0 has two distinct real roots. One root belongs to (-2,-1) and another root (2,3). It is also given that a-b+c>0. Find the sign of: 1) c , 2) b^2-4ac , 3) 3c-2a , 4) 4a-2b+c ,5) a+3b+c

Answers

Answered by shouryagautam
0

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