Given that the lcm of two numbers is 32and their product is 128 determine their HCF
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Solution :
______________________
If a ,b are two numbers and
their LCM = l and HCF = h then
a × b = l × h
_______________________
Here ,
l = 32 ,
a × b = 128,
h = ?
h × l = a × b
=> h = ( a × b )/l
=> h = 128/32
=> h = 4
Therefore ,
HCF = h = 4
••••
______________________
If a ,b are two numbers and
their LCM = l and HCF = h then
a × b = l × h
_______________________
Here ,
l = 32 ,
a × b = 128,
h = ?
h × l = a × b
=> h = ( a × b )/l
=> h = 128/32
=> h = 4
Therefore ,
HCF = h = 4
••••
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