Question

given that the line y=px+q passes through (1,-3) and (6,7).find the value of p and q​

Answer 1

Answer:

Given, equation of line :

2

y

=x−p

And, it passes through the point (−4,4)

Hence, it satisfies the line equation

So,

2

4

=(−4)−p

2=−4−p

p=−4−2

Thus, p=−6

Answer 2

Answer:

2=p+q+r

r=0

dydx∣x=0=1

dxdy=2px+q

q=1

2=p+1+0

p=1

please work bye this method sory I can't get answer