given that the mean of five numbers is 27
if one of the numbers is excluded the
mean gets reduced by 2. Determine the
excluded number
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Answer:
a+b+x+y+z=27×5
a+b+x+y+z=135….(1)
If one no. is excluded let it be ‘ a'
Mean of 4 nos. is 25
b+x+y+z/4=25
b+x+y+z=25×4
b+x+y+z=100….. (2)
So, (1) -(2)
a=(135–100) =35
Excluded number is 35
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