Given that the nth term Tn’ of a sequence is Tn = 6n + 5, find
i. The 6th term
ii. The 8th term
iii. The lowest common multiple of the 6th term and 8th term.
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2
Answer:
41
53
2173
Step-by-step explanation:
¡) the 6th term
It is of the form 6n+5
So 6th term will be
6(6)+5
41
¡¡) 8th term
6(8)+5 = 48+5 = 53
8th term is 53
We need to find lcm of 41 and 53
¡¡¡)
= 2173
The lcm is 2173
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