Question

. Given that the number 59142a is divisible. by 4, where a is a digit, what are the possible values of a?​

Answer 1

Answer:

To be divisible by 4 last two digits have to be divisible by 4

Step-by-step explanation:

So ans  is 4 and 8

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Answer 2

Question :-----

• Given that the number 59142a is divisible. by 4, where a is a digit, what are the possible values of a?

Concept used :-----

Divisibility Rule of 4 State that, If the last two digits of a whole number are divisible by 4, then the entire number is divisible by 4.

Solution :------

in the Given problem, 59142a ,,we just have to make 2a, divisible by 4 ..

lets put value of a , From 0 to 9 and check which are divisible by 4.

→ 20 = yes

→ 21 = No

→ 22 = No

→ 23 = No

→ 24 = Yes

→ 25 = No

→ 26 = No

→ 27 = No

→ 28 = Yes

→ 29 = No

we get, Total 3 Numbers = 20, 24 and 28 ..

If these Numbers in last, than the whole Number will Divisible by 4...

Hence, we can say that, Total 3 values of a , that are = 0, 4 and 8 are Possible....

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