Given that the number 60ab57377 is divisible by 99,where a and b are digits.what are the valueb
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Factors of 99 are 11×9.
If the given number is divisible by 9 and 11 it will be divisible by 99.
For the number to be divisible by 9 the sum of the number must be a multiple of 9.
For the number to be divisible by 11 the difference of the sum of the alternate digits must be 0 or multiple of 11.
If we satisfy these two conditions value of a and b will be found.
The number= 60ab57377
Sum= 35+ab.
Difference of sum of alternate digit=21+a-(14+but) value of a and b can be 0to9 as they are single digits.
If we put a= 7 and b= 3.
Sum= 35+7+3=45 divisible by 9.
Difference of sum= 21+7-(14+3)= 11 divisible by 11.
Hence,the number 607357377 is divisible by99.
a=7 b=3.
Sorry, It became so lengthy.
Hope it helps.
Factors of 99 are 11×9.
If the given number is divisible by 9 and 11 it will be divisible by 99.
For the number to be divisible by 9 the sum of the number must be a multiple of 9.
For the number to be divisible by 11 the difference of the sum of the alternate digits must be 0 or multiple of 11.
If we satisfy these two conditions value of a and b will be found.
The number= 60ab57377
Sum= 35+ab.
Difference of sum of alternate digit=21+a-(14+but) value of a and b can be 0to9 as they are single digits.
If we put a= 7 and b= 3.
Sum= 35+7+3=45 divisible by 9.
Difference of sum= 21+7-(14+3)= 11 divisible by 11.
Hence,the number 607357377 is divisible by99.
a=7 b=3.
Sorry, It became so lengthy.
Hope it helps.
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