Question

Given that the radius of the base of the two domes are 21 cm and 42 cm.

a) By how much is the volume of the larger dome greater than that of the smaller

dome?

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Answer 1

Given

• radius of dome 1= 21 cm
• radius of dome 2=42 cm

To find

• By how much is the volume of the larger dome greater than that of the smaller

Solution

volume of dome 1

2/3πr^3

=2/3×22/7×21×21×21

=19,404 cube cm

volume of dome 2

=2/3×22/7×42×42×42

=155,232 cube cm

difference of there volume

volume of dome 2- dome 1

=135,828 cube cm

Thanks

hope its helpful