Given that the real numbers s, t satisfy 19s² + 99s +1 = 0, t^2 +99t + 19 = 0 and st is not equal to 1, then the absolute value
st+4s+1÷t is
A.a prime number
B.divisible by 19
C.divisible by 5
D.divisible by 2
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Answer:
d
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