Question

Given that the reflective index of the glass is 1.5 and water is 1.33, Find the critical angle for a ray of light moving from glass to water

Answer 1

Answer:

μ

glass

​

=1⋅5

μ

water

​

=1.33

∴μ of glass w.r.t water,

ωμ

g

​

=

1.33

1.5

​

=1.1278

If C is the critical angle for glass-water interface, then

sinC

1

​

=

ω

μ

g

​

=1.1278

sinC=

1.1278

1

​

=0.8867

C=sin

−1

(0.8867).

Explanation:

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