Math, asked by shazadps1, 7 months ago

given that the square root of 4225 =65 find the value of the square root of 4225 plus square root of 42.25

Answers

Answered by DTSiPanda
5

Answer:

65+6.5=71.5.

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Explanation

2 digit decimal places square root gives 1 decimal place result.

Answered by ushmagaur
0

Answer:

The value of \sqrt{4225}+\sqrt{42.25} is 71.5.

Step-by-step explanation:

It is given that the square root of 4225 is 65.

\sqrt{4225} =65

To find:-

The value of \sqrt{4225}+\sqrt{42.25}.

Step 1 of 2

Consider the square root as follows:

\sqrt{42.25}

Rewrite the square as follows:

\sqrt{\frac{4225}{100} }

\frac{\sqrt{4225} }{\sqrt{100} } . . . . . (1)

The square root of 4225 is 65, i.e.,

\sqrt{4225} =65

And the square root of 100 is 10, i.e.,

\sqrt{100} =10

Then equation (1) becomes,

\frac{\sqrt{4225} }{\sqrt{100} }=\frac{65}{10}

        =6.5

Hence, the square root of 42.25 is 6.5.

Step 2 of 2

Consider the sum of square roots as follows:

\sqrt{4225}+\sqrt{42.25}

Substitute the values of \sqrt{4225} and \sqrt{42.25} as follows:

\sqrt{4225}+\sqrt{42.25}=65+6.5

                          =71.5

Final answer: The value of \sqrt{4225}+\sqrt{42.25} is 71.5.

#SPJ2

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