Question

given that the sum of zeros of p(x)=(a+1)x²+(2a+3)x+(3a+4) is -1, find the product of its zeros

Answer 1

hi friend,

given that the sum of zeros of p(x)=(a+1)x²+(2a+3)x+(3a+4) is -1

<> -(2a+3)/(a+1)=-1

<>2a+3=a+1

<>a=-2

so,we know that product of zeros = constant /x² coefficient

=3a+4/a+1

=-6+4/-2+1

=-2/-1

=2

I hope this will help u ;)