given that the sum of zeros of p(x)=(a+1)x²+(2a+3)x+(3a+4) is -1, find the product of its zeros
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hi friend,
given that the sum of zeros of p(x)=(a+1)x²+(2a+3)x+(3a+4) is -1
<> -(2a+3)/(a+1)=-1
<>2a+3=a+1
<>a=-2
so,we know that product of zeros = constant /x² coefficient
=3a+4/a+1
=-6+4/-2+1
=-2/-1
=2
I hope this will help u ;)
given that the sum of zeros of p(x)=(a+1)x²+(2a+3)x+(3a+4) is -1
<> -(2a+3)/(a+1)=-1
<>2a+3=a+1
<>a=-2
so,we know that product of zeros = constant /x² coefficient
=3a+4/a+1
=-6+4/-2+1
=-2/-1
=2
I hope this will help u ;)
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