Given that the two numbers appeating on throwing two dice are different fins the probability of the event
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Answered by
0
Answer:
1/15
Step-by-step explanation:
S = {(1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5)}
P(sum = 4) = 2/30 = 1/15
Answered by
0
Answer: 5/6
Step-by-step explanation:
Favourite outcome is 36-6(having same number on both dice)
Total possible outcome is is 36
So p(getting different number)= 30/36
=> 5/6
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