Math, asked by Adeela19801, 10 months ago

Given that the two numbers appeating on throwing two dice are different fins the probability of the event

Answers

Answered by dvppriya3
0

Answer:

1/15

Step-by-step explanation:

S = {(1,2) (1,3) (1,4) (1,5) (1,6)

       (2,1) (2,3) (2,4) (2,5) (2,6)

       (3,1) (3,2) (3,4) (3,5) (3,6)

       (4,1) (4,2) (4,3) (4,5) (4,6)

       (5,1) (5,2) (5,3) (5,4) (5,6)

       (6,1) (6,2) (6,3) (6,4) (6,5)}

P(sum = 4) = 2/30 = 1/15

Answered by Fuhad
0

Answer: 5/6

Step-by-step explanation:

Favourite outcome is 36-6(having same number on both dice)

Total possible outcome is is 36

So p(getting different number)= 30/36

=> 5/6

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