Math, asked by pappaypaul961, 11 days ago

Given that the zeroes of the quadratic polynomial x^2 + (a + 1) x + b are 2 and -3, what is a and b ???? PLS

Answers

Answered by michaellaselby
0

0 and -6

Step-by-step explanation:

x=2 , x=-3

x-2 , x+3

(x-2)(x+3)

x²+x-6

a+1 = 1

a=0

b=-6

Answered by gindravanshdeep
0

Zeroes of a polynomial is all the values of x at which the polynomial is equal to zero.

2 and - 3 are the zeroes of the polynomial p(x) = x2 + (a + 1)x + b

i.e. p(2) = 0 and p(- 3) = 0

p(2) = (2)2 + (a + 1)(2) + b = 0

= 4 + 2a + 2 + b = 0

= 6 + 2a + b = 0 (

P(- 3) = (- 3)2 + 9 + (a + 1)(- 3) + b = 0

= 9 - 3a - 3 + b = 0

= 6 - 3a + b = 0(2)

hope it was helpful

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