Question

given that triangle abc is an isosceles right triangle with ac is equal to bc and angle acb is equal to 90 degree d is a point on ac and he is on the extension of bd such that a perpendicular be if a is equal to how bd prove that bd bisect angle abc

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

In tringle ABD & ACD

AB=AC (GIVEN)

ANGLE ADB=ANGLE ADC(BOTH ARE RIGHT ANGLES)

AD=AD(COMMON)

SO BOTH THE TRIANGLES ARE CONGRUENT

THEREFORE BD=CD(CPCT)

ANGLE BAD=ANGLE CAD(CPCT)

HENCE AD BISECTS BOTH BC AND ANGLE A

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