Question

Given that two adjacent angles to parallelogram
are (3 x-4)^0 and (3x+16)^0 find the value of x
Also find the measure of each its angles.​

Answer 1

since opp sides of a llgm are ll the the adj angles are corresponding i.e sum is 180
now acc to the question
3x-4+3x+16=180°
6x+12=180
6x=180-12
x=168/6
x=28