Question

given that two of the cubic polynomial ax3+bx2+cx+d are 0 , the third zero is
pls fast​

Answer 1

Answer:

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Step-by-step explanation:

dusudhdhsbnsnsanmakakqkananamskdxi I have to be a good day at work and I don't know what I want to be a good day and with me for my phone is on the phone with my mom is going to be a good day at work and I don't know what I want to be a good day at

Answer 2

Answer:

-b/a

Step-by-step explanation:

GIven,  two roots of ax³+bx²+cx+d=0 are 0,0.

Sum of the roots of this polynomial is -b/a

Let the unknown root be A

therefore 0+0+A= -b/a

A= -b/a.

Additional:

Let the given polynomial be f(x).

∴f(0)= 0

a(0)³+b(0)²+c(0)+d=0

⇒d=0.

Also sum of roots taken two at a time is c/a

Therefore, (0)(0) +(A)(0)+(0)(A)=c/a

⇒c=0.