Given that two of the zeroes of the cubic polynomial ar3 + bx + cx + d are 0, the third zero is
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let the roots be p ,q ,r
two root let p and q be 0 (given)
we know that => sum of roots = -b/a
=> p + q + r = -b/a
=> 0 + 0 + r = -b/a
=> r = -(b/a)
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