Given that two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0, the third zero is
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Answer:
the third zero is minus d
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Step-by-step explanation:
Given two zeroes of a cubic polynomial
(ax³ + bx² +cx + d) are zero.
Let third zero be y
then sum of zeroes = (−b/a)
⇒0+0+y = (–b/a)
⇒y = (−b/a)
So the answer is (–b/a)
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