given that two of the zeros of the cubic polynomial ax^3+bx^2+cx+d are 0,the third zero is
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Answer:
The third zero is -b/a
Step-by-step explanation:
Given:
Two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0
Let zeroes of the equation be p, q, r
According to question,
=>Two zeroes [ p, q ] = 0, 0
We know,
=>Sum of roots = -b/a
Therefore,
By using relation between zeroes and coefficient of polynomial, we have:
=>p + q + r = -b / a
Substituting the values of p and q,
=>0 + 0 + r = -b / a
=> r = -b/a
=>Third zero = r = -b/a
Hence,
The third zero is -b/a
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