Question

given that two of the zeros of the cubic polynomial ax3+bx2+cx+d are 0,the value of c is​

Answer 1

${\huge{\purple{\mathbb{\bold{ANSWER}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

▪︎ Zeroes of cubic polynomial = 0.

${\large{\blue{\bold{\underline{To\:Find:-}}}}}$

▪︎ The value of c.

${\large{\blue{\bold{\underline{Concept\:Used:-}}}}}$

▪︎ Product of zeroes taken two at a time,

= Coefficient of x/Coefficient of x³.(c/a)

${\large{\blue{\bold{\underline{Now,}}}}}$

=》 (0+0)×(0+0)×(0+0) = c/a.

=》 0 = c/a.

=》 c = 0×a.

${\large{\green{\boxed{\bold{=》\:c\:=\:0.}}}}}$

☆ Therefore the required value of c is 0.

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Answer 2

Answer:

Step-by-step explanation:

Let p,q and r be zeros of given polynomial such that p = 0 and q = 0.

We know that , pq + qr + rp = c/a

---> 0×0 + 0×r + r×0 = c/a

---> 0 = c/a

---> c = 0

Hence, option C is correct.

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