Question

Given that u is a vector of magnitude 2, v is a vector of magnitude 3 and the angle
between them when placed tail to tail is 45°, what is u.v?
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Answer 1

Answer:

u.v= uvcos(theta)

here magnitude of u=2

magnitude of v=3

and angle (theta)=45°

So u.v=2×3×cos45°

u.v=6×1/√2

u.v=3√2

Hope it helps!

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