Question

GIVEN THAT
W=200 J
M=10KG
G=10M/S
S=4M
A=??​

Answer 1

Answer:

Given that,

Mass of object, m=10Kg

Velocity, v=10m/s

Vertical distance, h=10m

From work energy theorem:

Work done by weight + work done by air = KE

W

air

=KE−W

weight

=

2

1

mv

2

−mgh

=

2

1

×10×10×10−10×10×10

=−500J

The work done by the push of air on the object is -500 J.

Answer 2

Answer:

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